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What is some good advice for specifying allowable pressure drops in shell and tube exchangers for heavy hydrocarbons?


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More Chemical Engineering Interview Questions

Question 38 - The terminal velocity of a falling object, v is given by v = sqrt [ 4g (R - r) D / (3Cr) ] where sqrt is the square root of, g = 9.81, D = 0.000208, R = 1800, r = 994.6, m = 0.000893. The Reynold number, L is given by L = rD (v) / m. The C for various conditions are : C = 24 / L for L < 0.1; C = 24 (1 + 0.14 L^0.7) / L for 0.1 <= L <= 1000; C = 0.44 for 1000 < L <= 350000; C = 0.19 - 80000 / L for 350000 < L. Find the value of v for the situation above by trial and error, ^ is power, <= is less than or equal to.

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QUANTUM BIOLOGY - EXAMPLE 33.10 : The wavefunction starts out in a superposition of possible states in a closed black box like this : Ψ (kitty) = 0.7071 Ψ (alive) + 0.7071 Ψ (dead) where Ψ (kitty) = wavefunction of a kitten, Ψ (alive) = wavefunction of a living kitten, Ψ (dead) = wavefunction of a dead kitten. By prediction and calculation, find the probability of : (a) a living kitten inside the black box; (b) a dead kitten inside the black box.

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What is the main difference between deflection and null type instruments?

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What is the difference between coagulation and flocculation in water treatment plant?

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How can the particle size distribution be determined in a given bulk solid?

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send previousyear question paper for ongc gt 2011 chemical engineering written exam

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What are the reasons of removal of particles from effluent gas?

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ENVIRONMENTAL ENGINEERING - QUESTION 22.2 : Biochemical Oxygen Demand (BOD) could be calculated using the formula BOD = (DOi - DOf) (Vb / Vs) where Vb = Volume of bottle in ml, Vs = Volume of sample in ml, DOi = Initial dissolved oxygen in mg / L, DOf = Final dissolved oxygen in mg / L. (a) By using a bottle of Vb = 300 ml with sample Vs = 30 ml, find the BOD if DOi = 8.8 mg / L and DOf = 5.9 mg / L. (b) By using a bottle Vb = 600 mL with sample Vs = 100 mL, find the BOD if DOi = 8.8 mg / L and DOf = 4.2 mg / L. (c) Find the average BOD = [ Answer of (a) + Answer of (b) ] / 2. (d) If the BOD-5 test for (a) - (c) is run on a secondary effluent using a nitrification inhibitor, find the nitrogenous BOD (NBOD) = TBOD - CBOD. Let TBOD = 45 mg / L and CBOD = Answer of (c).

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Why is post-weld heat treatment (stress relieving) sometimes necessary for welded vessels?

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Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt % methanol and the second contains 70.0 wt % methanol. If 200 kg of the first mixture is combined with 150 kg of the second, what are the mass and composition of the product? The symbol of weight percent is wt %.

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What are pcbs?

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Explain some of the consequences of an undersized kettle type reboiler?

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