Answer / kangchuentat

NATURAL GAS ENGINEERING - ANSWER 26.3 : Mass of carbon dioxide emitted by natural gas-fired electric power generation for every megawatt hour generated = 2000 / 2 = 1000 pounds = 1000 pounds x (0.4536 kg / pound) x (metric ton / 1000 kg) = 0.4536 metric tons. Total energy generated by natural gas in the world for year 2012 = 6799 million metric tons x (megawatt hour / 0.4536 metric tons) = 14988.977 million megawatt hour = 14988977 gigawatt hour, approximately. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

i badly need a chemical process details for making a project...plz help me out......i m a btech final yr chemical engg student in a govt univ,and we have to make a detailed project on any chemical process with contents like...intro,kinetics , material balance,thermodynamics,process layout,process design,physical conditions,plant location,cost estimation etc.............if any one could help me i will never forget hi thankless work and always try to help u in whatever u ask.............

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In a screw compressor air is sucked from atm and mixes with the oil and is separated using separators.Will the viscosity of the oil get affected as moisture in air gets mixed with oil?

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In a selection of suitable heating equipment for drying of crystals of biochemical, the one of the lowest current consumption will be chosen for safety consideration. Selection is available : (A) 120 V microwave oven 1800 W. (B) 240 V conventional oven 11000 W. Which one should be chosen and why?

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I have Completed my B.Tech in Chemical Engineering from NIT Raipur, I want to prepare for HPCL Please Suggest me some books for Aptitude, Technical Questions & Please send me Previous Year Question Papers.

3 Answers   HPCL,

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If sum one has HAL placement paper plz mail me ,I m Chemical Engg.my id is er.kotnala@gmail.com

0 Answers   HAL,

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CHEMICAL ENERGY BALANCE - EXAMPLE 11.5 : According to Margules Equation, P = x(1) p(1) g(1) + x(2) p(2) g(2) for a two-component mixture where P is bubble pressure, x is mole fraction, p is saturation pressure, g is constant given by ln g(1) = x(2) A x(2). Find the value of A as a constant when P = 1.08 bar, p(1) = 0.82 bar, p(2) = 1.93 bar in a 50 : 50 mole fraction mixture. Estimate the pressure required to completely liquefy the 30 : 70 mixture using the same equation, by proving P = 1.39 bar. Take note that ln g(2) = x(1) A x(1), ln g(1) = x(2) A x(2).

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sir i am appearing in railway exam of section engineer and my branch is chemical engineering i want previous question paper of section engineer of chemical branch please tell me as soon as possible my email id is surendrasaroj18@gmail.com THANKYOU

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What is meant by surging in compressors?

5 Answers   CPCL,

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What is difference between overall heat transfer coefficient & individual heat transfer coefficient?

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Explain how can viscosity affect the design of a mixer?

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Question 60 – During the landing process of an airplane, the velocity is constant at v. (a) If the displacement of the plane is x at time t, find the differential equation that relates t, x and v. (b) The plane has 2 parts of wheels – the front and the back, separated by a distance L. The front part of the wheel touches the land first, that allows the straight body of the plane to form an angle T with the horizontal land. If the vertical distance between the back part of the wheel and the horizontal land is y, find the equation of y as a function of L and T. (c) Find the differential equation that relates dy as a function of dt, v and sin T. (d) Find the differential equation that consist of dy as a function of y, L, v and dt. (e) Find the equation of y as a function of v, L, t and C where C is a constant. (f) When t = 0, prove that y = exp C as the initial value of y.

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ACCOUNTING AND FINANCIAL ENGINEERING - EXAMPLE 34.34 : A biochemical engineering company has stock P = 20,000 shares of M % preferred stock of Q = $100 par and N number of shares of $20 par common stock. In year 1 : $10,000 is distributed as dividend. In year 2 : $25,000 is distributed as dividend. Let (Total Dividend) = (Dividend for Preferred Stock) + (Dividend for Common Stock). (a) In year 1, calculate the amount distributed as dividend for preferred stock, when no dividend was distributed for common stock. (b) In year 2, the amount distributed for common stock was $5000. Find the values of M and N, when the dividend per share for common stock is $0.05.

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