Answer / vinoth

1

Answer / preethi sundararajan

Give a little amount of drink from each bottle with a time gap of some minutes and notice the time.
Start calculating time if death starts, so that the poisoned bottle can be found.

i.e.,
At 1st min the mouse tastes 1st bottle, if it is poisoned then it dies at 10 hr 1 min.
After 15 mins the mouse tastes 2nd bottle, if it is poisoned then it dies at 10 hr 15 min
After 30 minutes the mouse tastes 3rd bottle, if it is poisoned then it dies at 10 hr 30 min
Proceeding like this,
After 4 hrs 30 mins the mouse tastes 19th bottle, if it is poisoned then it dies at 14 hrs 30 min
If the mouse is still alive after 14 hrs 30 min, then the poison will be in the 20th bottle.

Hence the answer is 1.

Answer / shelton_anton

if the time of death is approximated in hours..........3 mice will be enough to get deducted in 16 hrs
if the time of death is approximated in minutes.......1 mice will be enough to get deducted in 10 hrs 20 minutes
if the time of death is approximated in seconds......1 mice will be enough to get deducted in 10 hrs 00 minutes 20 seconds
if the time of death is approximated in milliseconds..1 mice will be enough to get deducted in 10 hrs 00 minutes 00 seconds 20 milliseconds
if the time of death is approximated in microsecond which is not possible by medical criteria that the person will die accurately when the time 10 hrs 00 minutes 00 seconds 00 milliseconds and 20 microseconds elapses. even though if theoritically possible wil also use 1 mice to get deducted.

Else if anyone is willing to say hypothetical question could also be the answer......

Answer / achudan ts

The answer is 5.
Cannot explain without a table.
Little digital logic truth table is used.
With 5 rats you can check from 17 to 32 bottles.
2^4 <= 20 > 2^5. Therefore answer is 5.

Answer / sivakumar

3

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