Give the output of the following program
main()
{int ret;
ret=fork();ret=fork();ret=fork();ret=fork();
if(!ret)
printf("sun");
else
printf("solaris");
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Answer / rojoco
Imagining that the correct headers were included and the
closing bracket for the main function is added, it'll print
sun 8 times and solaris 8 times. You won't know the order
that they're printed in, it depends on the kernel scheduler
as to which process is run first.
| Is This Answer Correct ? | 11 Yes | 1 No |
Answer / imran
I dont't think this will compile as its missing a closing
brace.
| Is This Answer Correct ? | 13 Yes | 5 No |
Answer / anupam mittal
The ans depend on the value returned by the fork function
there is no fork function defined so we can not predict he
ans
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / pdp
It depends on the return value of fork(). If it is other
than 0 (zero), then the output is solaris else sun.
| Is This Answer Correct ? | 6 Yes | 5 No |
Answer / prasanna
It will print solaris first and then sun... A sequence of
solarissun if there is a closing brace at the end..!!
| Is This Answer Correct ? | 1 Yes | 4 No |
Answer / saurabh singh
first of all it will not execute bec of 2 reasons:
1.it doesn't have a closing braces.
2.fork() function is not defined anywhere.so it will show
an error.
| Is This Answer Correct ? | 2 Yes | 5 No |
Give the output of the following program main() {char *p='a'; int *i=100/*p; } what will be the value of *i= 1
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