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what is strcture
i++ i ++i answer to this i=5 what is the out put
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My answer is
1.
#include<iostream>
using namespace std;
int main()
{
int i = 5;
cout << ++i << i << i++ << endl;
return 0;
}
ANS:765
2.
#include<iostream>
using namespace std;
int main()
{
int i = 5;
cout << ++i ;
cout << i ;
cout << i++ << endl;
return 0;
}
ANS:666
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / shivendra
The o/p will be as follows:-
666
reason:- in c++ in cascading the processing will be from
RHS. hence first "++i" will be executed and gives value 6.
after that "i" is executed as 6 and finally "i++" which will
also give 6.
one thing to notice here is that printing will be as usual
i.e. from left to right. So if the structure was "++i i i++"
then o/p will be 765
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / osama
The answer is undefined since you are modifying a built in
type in sequence without a sequence point in between.
| Is This Answer Correct ? | 0 Yes | 1 No |
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