Answer / kang chuen tat (malaysia - pen

Answer 32 : Rearranging the equation gives P v^3 – (Pb + RT) v^2 – av + ab = 0. By using Excel program of computer v = 0.19322. Solver : FILE -> Options -> Add-Ins -> Solver Add-in. Goal seek : DATA -> What-If-Analysis -> Goal Seek. In both functions, Set cell / Objective, To value / Value Of, By changing cell / Changing Variable Cells should be used where To value / Value Of = 0, By changing cell / Change Variable Cells is the assumed v value, Set cell / Objective is the equation of function. The answer is given by Kang Chuen Tat; PO Box 6263, Dandenong, Victoria VIC 3175, Australia; SMS +61405421706; chuentat@hotmail.com; http://kangchuentat.wordpress.com.

What is the basic difference between dispersion & distribution in any polymer blend or alloy??

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3 Answers   IOCL, ONGC,

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Question 108 - (a) The correct statement about both the average value of position (<x>) and momentum (<p>) of a 1-dimensional harmonic oscillator wavefunction is <x> = <p> = 1 - x. Find the value of x. (b) The probabilities of finding a particle around points A, B and C in the wavefunction y = f(x) are P(A), P(B) and P(C) respectively. Coordinates are A (3,5), B (4,-10) and C (6,7). Arrange P(A), P(B) and P(C) in term of a < b < c, when | y-coordinate | signifies the probability.

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Question 33 – By using Excel program either on laptop or desktop PC, solve the differential equation dy / dx = -2y + x + 4 with h = 0.005, initial values : x = 0, y = 1. The 4th order Runge-Kutta method provides : y(N + 1) = y(N) + (1/6) (k1 + 2k2 +2k3 + k4), k1 = h [ -2y(N) + x(N) + 4 ], k2 = h { -2 [ y(N) + k1 / 2 ] + x(N) + h / 2 + 4 }, k3 = h { -2 [ y(N) + k2 / 2 ] + x(N) + h / 2 + 4 }, k4 = h { -2 [ y(N) + k3 ] + x(N) + h + 4 }. What is the value of y at x = 0.5?

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Explain what are the affinity laws associated with dynamics pumps?

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MY generator water cooler inlet line height - 11 mtr inlet water line height - 7 mtr water come into the line from overhead tank, O/H tank height - 20 mtr the first tapping in the inlet line is 2" line which down to 4 mtr level plateform., second tapping in inlet water line goes to a pump 6" line installed at 4 mtr level plateform, pump capacity 200m3/hr, head- 30 mtr, hp-40. the outlet of pump of 6" water line connected to a header of 6 mtr long of 6" line, on this header the six tapping are connected, 4 nos. 3" line goes to 11 mtr height water cooler the pressure of the line is 0.15 to 0.25 kg/cm2, 2" and 4" pipe line connected to a cooler at 4 mtrlevel plateform. my question is, at 11 mtr height level the quantity of water and flow is not sufficient for my cooler, the temp. of cooler is rises much more. you are requested to suggest the modification of pipe line/ pump for take more water flow and pressure (desired pressure is 1 kg/cm2)

0 Answers   Simbhaoli Sugars,

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What are some good tank mixing rules of thumb?

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Hi, few days back i attended an interview. Currently my employment status is contract basis and interviewer didn't ask me abt mode of employment and he is thinking that am permanent employee in this organization and during the time of joining how I would avoid this problem.

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CHEMICAL MATERIAL BALANCE - EXAMPLE 2.4 : A mixture consists of benzene (B), toluene (T) and xylene (X). At a temperature of 353 K, the data of vapor pressures : B : 754.12, T : 289.71, X : 91.19. Unit is mm Hg. The pressure P is 0.5 atm. The value of k for each substance is k = (vapor pressure) / P. (a) Calculate k for B, T and X. Let L / V = 0.65. (b) By using the equation V = F / [ (L / V) + 1 ], find the value of V when F = 100, then what is the value of L?

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