Answer / harika nukala

M25= 1:1:2
VOLUME = 1+1+2=4
TOTAL VOL OF DRY MIX =1.54
CEMENT = 1/4(1.54*1440)=554.4 Kgs = 554.4/50 = 11 BAGS
SAND= 1/4(1.54)= 0.38 CUM
AGGREGATE = 2/4(1.54)= 0.77 CUM

Answer / vikas d v

m25=1:1:2
for 1cum add 50% for wet mix so 1.5cum
1.50/4=0.375cum
for 1cum=1440/50=28.8 approximately 30bags

cement=0.375*30=11.25bags
sand=0.375*1=0.375cum
aggregate=0.375*2=0.75cum

Answer / harish dutt pandey

it is depends upon mix design .in nominal mix we can used 370 kg.

WHAT IS IS CODE FOR USE TOR & TMT STEEL

1 Answers  

---

explain the rale of the government in the construction industry

0 Answers   SP Singla,

---

what happened if the diameter of capillary tube is double then the capillary rise will be

7 Answers   Bhel,

---

What are the reasons for geotechnical site investigations in uganda?

0 Answers  

---

what will be the lap length of column reinforcement in case of welded lap

2 Answers  

---

What is meant by hydration of cement??

7 Answers  

---

how many numbers of 4inch bricks and get consumed in 9 inch BB masonary wall in cubic feet.plz send my below e.mail adress

0 Answers   Quaid-e-Azam International Hospital,

---

the diff bet face left & face right observation of theodolite is 3' the error is 45'' 1'30'' 3' 0'

1 Answers  

---

Explain the difference between shear and tensile strength.

0 Answers  

---

which size of box use of cement,sand,aggregate to use the m 20 concrete. i know the quantity of material cement 400 kg or 8 beg ,662 kg sand and 1200 kg aggregate. i can use only 1 beg cement so pls give me answer . thx in advance

4 Answers   HCC,

---

how much tempareture are required to make liquid state of pid leed

0 Answers   IVRCL,

---

how to calculate the quantaty of steel in footing please show me detail procedure with the help of drawing

2 Answers  

---