how to get the particular chr in an array list the question
is ....i have an array like this
ABCD
EBCF
GBCH
IBCJ
HERE I NET TO GET ONLY "BC" FROM ALL HOW TO GET IT
HELP ME ANY ONE
THANKS
Answers were Sorted based on User's Feedback
Answer / gabbar
a="ABCD EBCF GBCH IBCJ"
b=Split(a," ")
For i=LBound(b) to UBound(b)
msgbox "count: "&i&" "& mid(b(i),2,2)
Next
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / koteswar
str = " ABCD EBCF GBCH IBCJ HERE I NET"
n = split(str, "BC")
cnt = ubound (n)
msgbox cnt
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / snegha
ar2=Array("ABCD","EBCF","GBCH","IBCJ")
arlen=UBound(ar2)-lbound(ar2)+1 'Finding array length
For p= 0 to arlen-1
msgbox Mid(ar2(p),2,3)
Next
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / dinesh1433
Dim AR2,i
AR2=Array("ABCD","EBCF","GBCH","IBCJ")
For i=0 to ubound(AR2)
If (Instr(AR2(i),"BC")<>0) Then
msgbox "BC found in Element :"&AR2(i)
End If
Next
| Is This Answer Correct ? | 2 Yes | 1 No |
Answer / rajesh
hai.. Koteswar
i need to say thanks for your quick reply ..
but my question is how to get BC IN A ARRAY means i need to
display it.....,BUT YOU ANS THAT HOW MANY BC ARE THERE IN
THE ARRAY LIST .....IF POSSIBLE PLEASE GIVE A COMMANDS AGAIN...
| Is This Answer Correct ? | 0 Yes | 0 No |
This will print BC 4 times.
a="ABCD EBCF GBCH IBCJ"
b=Split(a," ")
For i=0 to ubound(b)
msgbox mid(b(i),2,2)
Next
| Is This Answer Correct ? | 0 Yes | 0 No |
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