#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break;

#include<stdio.h>
main()
{int i=1;j=1;
for(;;)
{if(i>5)
break;
else
j+=1;
printf("\n%d",j)
i+=j;
}
}

Question Posted / sandhyait

Answers were Sorted based on User's Feedback

#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break; else j+=1; printf(..

Answer / jitendra mahajan

2
5

Is This Answer Correct ?

75 Yes

6 No

#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break; else j+=1; printf(..

Answer / vijay pal

2
5

Is This Answer Correct ?

18 Yes

0 No

#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break; else j+=1; printf(..

Answer / radha raman

2
3

Is This Answer Correct ?

13 Yes

8 No

#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break; else j+=1; printf(..

1
1
1
1
1

Is This Answer Correct ?

1 Yes

4 No

#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break; else j+=1; printf(..

Answer / sourav basu

1 1

print statement is printing 'j', not 'i'. and the for loop works on the basis of value of 'i'..
tested and verified answer on gcc compiler

Is This Answer Correct ?

2 Yes

5 No

#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break; else j+=1; printf(..

Answer / vedansh

2
3

Is This Answer Correct ?

2 Yes

6 No

#include<stdio.h> main() {int i=1;j=1; for(;;) {if(i>5) break; else j+=1; printf(..

Answer / ajay

error loop is incomplete

Is This Answer Correct ?

2 Yes

6 No