char S;
char S[6]= " HELLO";
printf("%s ",S[6]);
output of the above program ?
(0, ASCII 0, I,unpredictable)
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Answer / kiran kumar
For the Above Program u will get the Error as Conflictinf
types for S because you are declaring 2 variables of
different types one as char and another as char aray with
same names.
So, the compiler will be in Unpredicatable stage
variable name S to be consider for what type and it will
give Error as Confilctinf types for S.
Even if u replace any of the S with s then u will get the
Output of this Program as Segfault in Linux where as in
Windows u will get the HELLO.
To the Best of my Knowledge i Posted this Answer.
Let me Know if there is any better Clarifications.
My emai Id is kirjony@gmail.com
| Is This Answer Correct ? | 2 Yes | 0 No |
Answer / divakar & venkatesh
u will get the following error
conflicting types for 'S'
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / prasanth
IT`LL SHOW AS MULTIPLE DECLATION FOS S AND WE`LL NOT OBTAIN
THE OUTPUT
| Is This Answer Correct ? | 0 Yes | 2 No |
Answer / manishsoni
This gives an error, and prg is terminated.
To slove this problem we show a program..
#include<stdio.h>
#include<conio.h>
int main()
{
char S[6]= "HELLO";
printf("%s",S);
getch();
return 0;
}
this print simple hello.
| Is This Answer Correct ? | 0 Yes | 2 No |
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