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#include<stdio.h>
main()
{int i=1;j=1;
for(;;)
{if(i>5)
break;
else
j+=1;
printf("\n%d",j)
i+=j;
}
}
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Answer Posted / sourav basu
1 1
print statement is printing 'j', not 'i'. and the for loop works on the basis of value of 'i'..
tested and verified answer on gcc compiler
| Is This Answer Correct ? | 2 Yes | 5 No |
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