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#include<stdio.h>
main()
{int i=1;j=1;
for(;;)
{if(i>5)
break;
else
j+=1;
printf("\n%d",j)
i+=j;
}
}
- 7 Answers
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Answer Posted / ajay
error loop is incomplete
| Is This Answer Correct ? | 2 Yes | 6 No |
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