Answer / harish

only #2 is d right answer......XOR yields...perfect answers.....

Answer / balasubramanian ganapthi

a=a+b-(a=b);

This is the example by using only one line to swap the two
variables without using the third variable.

Answer / ashesh anand

Thanks Guys....
#2 is absolutely right...

Answer / xeon

To note on the answer about Perl, it uses a third variable
and just doesn't tell you. The C++ equivalent is:

//Our data
class exampleclass {};
exampleclass classa, classb;
int inta, intb;
float floata, floatb;

//Our swap function
template<class T>
void swap(T *a, T *b) {
T temp = *a;
a = b;
*b = temp;
}

//Our use of the swap function
swap<classexample>(classa, classb);
swap<int>(inta, intb);
swap<float>(floata, floatb);

And also note, Perl is an interpreted (Script) language, so
though it is simple and robust, it is less efficient than a
language that is compiled.

Answer / dipak

#51 is perfect solution.

Answer / raja sekhar sharma

a=a+b;
b=a-b;
a=a-b;

Answer / ankit goel

Sorry i dont know..??
only 1st ans is write......
so give me positive marking....
Thank You...

Answer / pallabi

if any one of the variables eithet A or B is negative or
else both r negatibe then how logic will vary in cobol?

Answer / indu b

a=10;
b=20;
a=a+b;
b=a-b;
a=a-b;
a=20,b=10;

Answer / sriram

Hey guys, what about swaping variables contains string
values? All of your solutions will suck... Try this and swap
any datatype without third variable... Happy Sensible Coding..

$v = 'sriram';
$u = 'lakshmi';

$v .= $u;
$u = substr($v,0,(strlen($v) - strlen($u)));
$v = substr($v,(strlen($v) - strlen($u)-1), strlen($v));

echo 'u = ' . $u .'<br>';
echo 'v = ' . $v;

Which version do you prefer of the following two, 1) printf(“%s”,str); // or the more curt one 2) printf(str);

1 Answers  

void main() { static int i; while(i<=10) (i>2)?i++:i--; printf(“%d”, i); }

2 Answers  

#include<stdio.h> void fun(int); int main() { int a; a=3; fun(a); printf("\n"); return 0; } void fun(int i) { if(n>0) { fun(--n); printf("%d",n); fun(--n); } } the answer is 0 1 2 0..someone explain how the code is executed..?

1 Answers   Wipro,

What are the following notations of defining functions known as? i. int abc(int a,float b) { /* some code */ } ii. int abc(a,b) int a; float b; { /* some code*/ }

1 Answers  

void main() { int i=10, j=2; int *ip= &i, *jp = &j; int k = *ip/*jp; printf(“%d”,k); }

1 Answers  

main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above

3 Answers   HCL,

main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }

1 Answers  

main() { signed int bit=512, i=5; for(;i;i--) { printf("%d\n", bit = (bit >> (i - (i -1)))); } } a. 512, 256, 128, 64, 32 b. 256, 128, 64, 32, 16 c. 128, 64, 32, 16, 8 d. 64, 32, 16, 8, 4

2 Answers   HCL,

main() { int i=5; printf("%d%d%d%d%d%d",i++,i--,++i,--i,i); }

7 Answers  

main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n %u %u ",j,k); }

1 Answers  

int i,j; for(i=0;i<=10;i++) { j+=5; assert(i<5); }

3 Answers   Cisco, HCL,

Display the time of the system and display the right time of the other country

1 Answers