Answer / vikram singh saini

Here is the link:
http://niitdeveloper.blogspot.com/2010/12/accept-integers-print-in-reverse-order.html

This code accepts integers or numbers from user and print
them in reverse order using linkedlist.

Answer / shruthirap

node *reverse(node *first)
{
node *temp = NULL;

if(first->next != NULL)
{
temp = reverse(first->next);
temp->next = first;
return first;
}
else
return first;
}
//The only catch is that the supposed to be first node after
reordering, has to be kept either in some global pointer or
passed back by function. That's it :)

main() { float f=5,g=10; enum{i=10,j=20,k=50}; printf("%d\n",++k); printf("%f\n",f<<2); printf("%lf\n",f%g); printf("%lf\n",fmod(f,g)); }

1 Answers  

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Give a one-line C expression to test whether a number is a power of 2.

10 Answers   Microsoft,

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char *someFun1() { char temp[ ] = “string"; return temp; } char *someFun2() { char temp[ ] = {‘s’, ‘t’,’r’,’i’,’n’,’g’}; return temp; } int main() { puts(someFun1()); puts(someFun2()); }

2 Answers  

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struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }

1 Answers  

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abcdedcba abc cba ab ba a a

2 Answers  

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#define prod(a,b) a*b main() { int x=3,y=4; printf("%d",prod(x+2,y-1)); }

1 Answers  

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1. const char *a; 2. char* const a; 3. char const *a; -Differentiate the above declarations.

3 Answers  

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main() { char *str1="abcd"; char str2[]="abcd"; printf("%d %d %d",sizeof(str1),sizeof(str2),sizeof("abcd")); }

1 Answers  

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Write a Program that Inputs 10 Numbers in an Array and Show the Maximum Number

2 Answers   Ace Info,

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create a C-code that will display the total fare of a passenger of a taxi if the driver press enter,the timer will stop. Every 10 counts is 2 pesos. Initial value is 25.00

0 Answers   Microsoft,

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All the combinations of prime numbers whose sum gives 32

1 Answers   HHH,

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main ( ) { static char *s[ ] = {“black”, “white”, “yellow”, “violet”}; char **ptr[ ] = {s+3, s+2, s+1, s}, ***p; p = ptr; **++p; printf(“%s”,*--*++p + 3); }

1 Answers  

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