Answer / kurt s

The code example is horrendous. But the answer:

No, it doesn't have to deal with the nested printf statements. The printed statement would look something like this:

x=9, y=9x=9, count of earlier print=8

it places the first printf's arguments on the stack, which includes another call to printf, which is placed on top. The variable x gets predecremented, so when the nested printf starts to print, x will be 9. Before the outer printf can be called, the inner printf needs to return, and printf returns an int equal to the length of the outputted string, which is "x=9, y=9", a string of length 8. Note that this is still sent to STDOUT, printing to the screen.

The outer printf call looks like this now:

printf("x=%d, count of earlier print=%d", 9, 8);

Which prints "x=9, count of earlier print=8" to STDOUT, right after the inner printf's output, giving the string mentioned toward the top of this answer.

ld returned 1 exit status usually means there are unresolved symbols.

union u { struct st { int i : 4; int j : 4; int k : 4; int l; }st; int i; }u; main() { u.i = 100; printf("%d, %d, %d",u.i, u.st.i, u.st.l); } a. 4, 4, 0 b. 0, 0, 0 c. 100, 4, 0 d. 40, 4, 0

1 Answers   HCL,

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plz send me all data structure related programs

2 Answers  

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main() { void swap(); int x=10,y=8; swap(&x,&y); printf("x=%d y=%d",x,y); } void swap(int *a, int *b) { *a ^= *b, *b ^= *a, *a ^= *b; }

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#include <stdio.h> int main(void) { int a=4, b=2; a=b<<a+b>>2 ; printf("%d",a); return 0; }

0 Answers   Student,

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Write a routine to implement the polymarker function

0 Answers   TCS,

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main() { int i, j, *p; i = 25; j = 100; p = &i; // Address of i is assigned to pointer p printf("%f", i/(*p) ); // i is divided by pointer p } a. Runtime error. b. 1.00000 c. Compile error d. 0.00000

3 Answers   HCL,

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How to return multiple values from a function?

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main() { int i=-1; -i; printf("i = %d, -i = %d \n",i,-i); }

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How will you print % character? a. printf(“\%”) b. printf(“\\%”) c. printf(“%%”) d. printf(“\%%”)

4 Answers   HCL,

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why nlogn is the lower limit of any sort algorithm?

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main() { char p[ ]="%d\n"; p[1] = 'c'; printf(p,65); }

2 Answers  

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