In file1 have 80 records are like d1,d2,d3......D80. File2 have 1000records are like a1d1,a1d2,a3d3.....Etc. I want matching records in file3 ? Plse tell me the matching logic???I want answer only in cobol ?Not using any tool or jcl?
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Answer / animesh
It can be done using internal array table within the cobol program. first we will Move Record file in an aray with same Lrecl as the file1 and having 80 occurence.
Then again for file 2 we will populate another internal array table with 1000 occurence.
perform varying w-v-idx1 from w-k-1 by w-k-1 until
w-v-idx1> 80
perform varying w-v-idx2 from w-k-1 by w-k-1 until
w-v-idx2>1000
If w-v-file1(w-v-idx1) = w-v-file2(idx2)
Set some w-s-count = y
Add +1 to w-s-count
move -w-v-file1(w-v-idx1) to w-v-file3
write file 3 from w-v-file
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I have program P1 which calls file F1 which has 100 records and following structure 001 .................. 002 .................. 003 .................. 098 .................... 099 ................... 100 .................... Now I want to read these files and write these records in file F2 in following manner. 001 ...... 051 ..... 002 ...... 052 ..... 003 ...... 053 ..... .......... ....... .......... ....... .......... ....... 048 ........ 098 ...... 049 .......... 099 ....... 050 .... 100 ......
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