Answer / k.prakashchandra

The answer is correct .Just calculate the resistance of each
bulb.

Answer / p,btech student , e&e engg

Resistance of bulb
1(R=(V)^2/P)
=(110)^2/100 =121
ohm
resistance of blb 2
=(230)^2/200=264.5
ohm
so voltag drop
across bulb 2 will
be more (series
connection) .So
when connected in
series ,bulb 2 will
glow brighter.

Answer / zeeshan akbar

bulb 1 required 0.909 Ampere,
bulb 2 required 0.869 Ampere to full glow.

If we connect both in series.

same current will flow in both bulbs

bulb 2 required low current then bulb 1, so bulb 2 will
flow beter.

Answer / kalam akhtar

Sir will you plz explain how it is?

Answer / zeeshan akbar

230v.200w will glow beter

Answer / baskaran

first this question is not clear, because input voltage not
given this circuit.
ok
if input voltage 230 volts.
in series circuit Vt = Vr1 + Vr2
so each load gets 110 vols
so bulb 1 (110v,100w) glow brighter..

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