. There are two water tanks A and B, A is much smaller than
B. While water fills at the rate of 1 liter every hour in
A, it gets filled up like, 10, 20, 40,80, 160…..in tank B.
(At the end of first hour, B has 10 liters, second hour it
has 20 liters and so on). If tank B is 1/32 filled of the
21 hours, what is total duration of hours required to fill
it completely?
Answers were Sorted based on User's Feedback
Answer / sri
10+20+40+80+160
10(1+2+4+8+16)
this is a gp
first term=a
ratio=2
t21=1*2^20
x=2^25
therefore in gp
tn=ar^n-1
n-1=25
n=26
26 hrs
Is This Answer Correct ? | 15 Yes | 2 No |
Answer / puviyarasi
At the end of 4th hour 2/32 will be filled.
after 5th hour 4/32 will be filled
6th hour=8/32
7th hour=16/32
8th hour=32/32=1(full tank)
ans:8 hours
Is This Answer Correct ? | 0 Yes | 0 No |
Answer / srijeet majumder
since 1/32 filled in 3 hrs,in 4th hr it will b doubled(ie
2*1/32)=1/16 hr=5
1/16*2=1/8 hr=6
1/8*2=1/4 hr=7
1/4*2=1/2 hr=8
1/2*2=1 hr=9
Is This Answer Correct ? | 5 Yes | 9 No |
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