In the reading room of a library, there are 10 tables, 4
chairs per table. In each table there are different numbers
of people seated. How many ways they will sit in the
library so that no chair would be blank?
plz explain how can this quetions can b solved???
Answers were Sorted based on User's Feedback
Answer / samd singh
NONE...
d answer is none...
there is no way in which no chair wud b blank...
if in 1st table dere r 4 person ...
den in any other table dere will be max. 3 person
so 1 chair is left...
| Is This Answer Correct ? | 58 Yes | 11 No |
Answer / pallawi
ans is 6. coz in first table 4 will be seated. in second table 3 will be seated. in third table 2 will be seated. in fourth table 1 person will be sit. so out of 10 4 r filled and 6 r left.
| Is This Answer Correct ? | 50 Yes | 21 No |
Answer / sai
in my opinion there has to be one way ,so that no chair left empty.But in the options it gave c)2
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / noor
This is simple permutation...
40!
yes 40 factorial.
the first person may sit on any of the 40.
the next on any of the 39 remaining.
the next on any of the available 38 and so on...
hence leading to 8.15915283247898e+47
this may sound kinda cracked but the answer is:
815915283247897734345611269596115894272000000000
| Is This Answer Correct ? | 17 Yes | 49 No |
Answer / archna tiwari
the ans. is 40,because totel no. of chair is 40,so there in only 40 way to sit on it.
| Is This Answer Correct ? | 16 Yes | 60 No |
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