Write a program that takes a 3 digit number n and finds out
whether the number 2^n + 1 is prime, or if it is not prime
find out its factors.
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Answer / sumitgaur2010
#include<iostream>
#include<conio.h>
#include<math.h>
using namespace std;
int main()
{
int i,n,num,p=1;
cout<<"enter the number";
cin>>n;
num=pow(2,n)+1;
for(i=2;i<num/2;i++)
{
if(num%i==0)
{
p=0;
break;
}
}
if(p==1)
cout<<"prime";
else if(p==0)
{
cout<<"factors are";
for(i=2;i<num/2;i++)
if(num%i==0)
cout<<i<<",";
}
getch();
}
| Is This Answer Correct ? | 30 Yes | 19 No |
#include<iostream.h>
#include<conio.h>
int main()
{
int i,n,num,p=1;
cout<<"enter the number";
cin>>n;
num=pow(2,n)+1;
for(i=2;i<num/2;i++)
{
if(num%i==0)
{
p=0;
break;
}
}
if(p==1)
cout<<"prime";
else if(p==0)
{
cout<<"factors are";
for(i=2;i<num/2;i++)
if(num%i==0)
cout<<i<<",";
}
getch();
}
| Is This Answer Correct ? | 7 Yes | 4 No |
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