Here's the programm code:
int magic(int a, int b) {
return b == 0 ? a : magic(b, a % b);
}
int main() {
int a, b;
scanf("%d%d", &a, &b);
printf("%d\n", magic(a, b));
return 0;
}
on input stream we have integers 4, 45
What's the output integer?
How many times will be initiated "magic" function?
#include<stdio.h> #include<conio.h> void main() { char str[10]; int,a,x,sw=0; clrscr(); printf("Enter a string:"); gets(str); for(x=0;x<=a;a++); for(x=0;x<=a;x++) { if(str[x]==str[a-1-x]) { sw=1; } else sw=0; } if(sw==10 printf("The entered string is palindrome:"); else printf("The entered string is not a palindrome:); } getch(); } wht would be the explanation with this written code???
Faster Computers Suppose you have a computer that requires 1 minute to solve problem instances of size 1000. What instance sizes can be run in 1 minute if you buy a new computer that runs 1000 times faster than the old one, assuming the following time complexities T(n) for our algorithm? (a) T(n) = O(n). (b) T(n) = O(n3). (c) T(n) = O(10n).
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1+1/2!+1/3!+...+1/n!
write a program to calculate the radius for a quadratic equation use modular programming(function abitraction)hint use quadratic function
1 Answers ICAN, Jomo Kenyatta University,
U hv to enter a range from a and b and search hw many no. of times a pattern n. occurs between the range a and b. Eg :i/p:enter range :0 100 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 0 to 100:1 Eg :i/p:enter range :100 1000 Enter pattern: 13 o/p: the no. times 13 occurred betwwn 100 to 1000: (in this 13,113,131,132,133…139,213,313,…913 all these will be counted)
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