How many four digit numbers can be formed using the digits
1, 2, 3, 4, 5 (but with repetition) that are divisible by 4?
Can you help Alok find the answer?
a) 100 b) 125 c) 75 d) 85
Answers were Sorted based on User's Feedback
Answer / sumit kumar
The no divisible by 4 must have last two digit divided by four
so no formed can be
**12
**24
**32
**44
**52
repetation is allowed
so in **12
1st place can be filled in 5 ways
2nd also in 5 ways
there fore 5*5 ways=25
for **12 it is 25 ways
for all=25*5
=125
Is This Answer Correct ? | 205 Yes | 14 No |
Answer / shatanu kuila
This is a contradictory question.
Bcoz
Any number(minimum three digit number) will be divided by 4, when its last two digit is divided by 4. Here number can be formed through this way **12,**32,**52,**24 but in this problem we can repeat the digit also one formation is **44.
Now we can form those unknown two position 2^5 way (number can be repeated. So for five formation total number will be
=(2^5)5=160. but there is no option.
Is This Answer Correct ? | 4 Yes | 34 No |
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