Answer / rajasekar

(1) tan x = c
(2) sec x ? sec y = c
(3) sin x = c cos y
(4) cos x = c sin y

Answer / yasheen shahi

divide by SINx*COSy throughout.
this gives
(cosx/sinx)dx+(siny/cosy)dy=0
This is nothing but the derivative of
log(sinx)-log(cosy)

Answer / sangeetha

cosx/sinx)dx+(siny/cosy)dy=0
This is nothing but the derivative of
log(sinx)-log(cosy)+logc
log(sinx/cosy)=logc
sinx/cosy=c
sinx=c cosy

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