swap two no without using third variable
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Answer / srinathsv
Suppose the 2 variables be 'a' & 'b'
Then,do the following steps
a=a-b
b=a+b
a=b-a
eg:Say a=10;b=6.The output should be a=6;b=10
a=a-b=10-6=4
b=a+b=4+6=10
a=b-a=10-4=6
| Is This Answer Correct ? | 35 Yes | 5 No |
Answer / thunder
/* swapping two numbers without using temp*/
#include<stdio.h>
int main()
{
int a=10,b=5;
a=a*b;
b=a/b;
a=a/b;
print f("a : %d b: %d",a,b);
}
| Is This Answer Correct ? | 12 Yes | 4 No |
Answer / mik30
its very simple question and it can be easily solved by some
logical reasioning ablity...my answer is given below:
#include<stdio.h>
#include<conio.h>
int main()
{
int a=2,b=2;
a=a-b;
b=a+b;
a=b-a;
printf("%d%d",a,b);
getch();
return 0;
}
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| Is This Answer Correct ? | 8 Yes | 1 No |
Answer / v.bharathi
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b;
clrscr();
printf("\nenter a,b value");
scanf("%d%d",&a,&b);
a=a+b;
b=a-b;
a=a-b;
printf("\nafter swapping..\n%d%d",a,b);
getch();
}
| Is This Answer Correct ? | 10 Yes | 3 No |
Answer / rivers
ill just write the logic here
a= a xor b
b= b xor a
a= a xor b
Take an example and check for yourself ,it works!
| Is This Answer Correct ? | 9 Yes | 3 No |
Answer / ankit
if there are two no as int a,b;
then we could swap these two no's without help of third no
as........>>>>>>
EX-->
int a,b;
a=a+b;
b=a-b;
a=a-b;
| Is This Answer Correct ? | 8 Yes | 2 No |
Answer / tejesh49
dim a as integer
dim b as integer
dim c as integer
a=a+b
b=a-b
a=a-b
print a
print b
| Is This Answer Correct ? | 3 Yes | 7 No |
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