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A half wave rectifier is used to supply 50vdc to resistive
load of 800ohms the semiconductor diode has a forword
resistance of 25ohms,calculate ac voltage required?



A half wave rectifier is used to supply 50vdc to resistive load of 800ohms the semiconductor diode..

Answer / dhafer faisal

Answer:
Output d.c. voltage, Vdc = 50 V
Diode resistance, rf = 25 &#937;
Load resistance, RL = 800 &#937;
Let Vm be the maximum value of a.c. voltage required.
&#8756; Vdc = Idc × RL
= &#960;( )
× = ×
&#960; +
m m
L L
f L
I V
R R
r R
&#63726; &#63737; &#63727; = &#63738; &#63728; + &#63739;
&#8757; m
m
f L
V
I
r R
or 50 = 800
&#960; (25 800)
×
+
Vm
&#8756; Vm = &#960; 825 50
800
× × = 162 V
Hence a.c. voltage of maximum value 162 V is required.

Is This Answer Correct ?    15 Yes 6 No

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