while calculating demand in my company the present load in
kw is 212.... there 125kvar capacitor bank is installed by
spliting as 50 in departments...the diasplay in panek biard
shows 175kw... how could we know the amount of kvar used to
compensate the kva
what is conductor constant of raccun conductor
0 Answers CSPDCL-Chhattisgarh State Power Distribution Company Limited,
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Help need in transformer !? Hello Friends The parameters of 2300/230 v 50hz t/f is R1=0.286 ohm R`2=0.319 ohm Rc=240 ohm X1=0.73 ohm X`2=0.73 ohm Xm=49.2 ohm Secondary Load impedance ZL=0.387+J0.29 solve the exact equivalent circuit with normal voltage across primery.. I know every thing but i cant find CURRENT I1=? and I`2=? Please help me give solution or only Formula please please...
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lamination figures