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10.If 100 ! = 100 x 99 x 98 x … x 2 x 1, the maximum power
of 20 which will divide 100 ! is
1] 21 2] 22 3] 23 4] 24
Plz Explain
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Answer Posted / revathi
(100*99*..*1)/20^n.
20=2*2*5
so find the no of 5's present in the range.
it is 24.
ans:24
| Is This Answer Correct ? | 39 Yes | 4 No |
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