Answer / ashish madhavi

the answer is
initial velocity is 25 km/hr
and distance is 105 km
explanation
let distance = xKm and Velocity = yKm/hr
form 2 equations
total time = time from start to first break point+ time
from first breakpoint to destination
(time = distance/speed)
total time fromassumption = (x/y)
for first case
total time = (x/y)+(3/4){36 minutes converted into hrs}
time from start to first break point = (30/y)
time from first break point to destination = (x-30/(4/5y))
{since velocity has decreased to 4/5}
hence
x/y + 3/4 = 30/y + (x-30/(4/5y)) .......... equatiion 1
similarly equation 2 is derived from 2nd case given as:
x/y + 3/5 = 45/y + (x-45/(4/5y)) .......... equatiion 2
solving v get x=105
and y = 25
its seems to be lengthy in reading the solution but trust
me it wont take more than 2 mins to solve the question

Answer / ashutosh singh

Let divide the question in two parts:-
1:-travelling at 4/5th of actual speed from the problem point car is late by 45 min.
2:That is clear it will take 9 min less to cover up the distance with actual speed if car fails after 45 km.
soln:-
difference in 1st cond and second condition is 15 km and 9 min
if car travels with 4/5th speed it will take 5/4 time of actual means 1/4 time more than actual
but here only 9mins more so actual time =36 min
to cover up 15 km in 36 min
speed=15/(3/5)
speed=25km/hr
from second,it is late by 45 min with 4/5 speed
so 1/4 more than actual so
actual time would be= 180 min=3hr
25*3=75km from problem point
so total distance is=30+75=105km

Answer / anand

vi = 25kmph
d=105km

Answer / karan

initial velocity = 25 kmph

Answer / sunil kumar

intial velocity is 100 km/hr, distance between A and B is
90 km

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