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.There is a rectangular Garden whose length and width are
60m X 20m.There is a walkway of uniform width around garden.
Area of walkway is 516m^2. Find width of walkway:
1 2 3 4

Question Posted / soumya ir

Answers were Sorted based on User's Feedback



.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / chinmaya panda

let the width of rectangle be x
so the length & breath is increased by 2x(draw on a paper
then only u'll understand)
so new total area along with walkway is (60+2x)*(20+2x)
so (60+2x)*(20+2x)-60*20=516
=>(60+2x)*(20+2x)=1716
=>(30+x)*(10+x)=429=33*13
=>x=3
which is da width of gateway

Is This Answer Correct ?    174 Yes 10 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / anuja malviya

let whole width of garden=60+2x
let whole length of garden=20+2x
where x=common width of gateway
thus,
(60+2x)(20+2x)-1200=516
=>1200+120x+40x+4x^2-1200=516
4x^2+160x-516=0
=>x=3
ANS....................

Is This Answer Correct ?    44 Yes 2 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / karthikeyan

the area of walk way with width X is 2(60*x)+2*(20*x) = 516


120X+40X = 516

160 X = 516

X= 3.225 = 3 (approx)

Is This Answer Correct ?    28 Yes 15 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / sachin chauhan

let whole width of garden=60+2x
let whole length of garden=20+2x
where x=common width of gateway
thus,
(60+2x)(20+2x)-1200=516
=>1200+120x+40x+4x^2-1200=516
4x^2+160x-516=0
4(x^2+40x-129)=0
x^2+40x-129=0
x^2+43x-3x-129=0
x(x+43)-3(x+43)=0
(x+43)(x-3)=0

=>x=3,-43
but width can never be -ve
so answer is 3 meter

Is This Answer Correct ?    11 Yes 1 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / rohan

2(60x)+2(20+x)*x=516,
solve for x,
x=3

Is This Answer Correct ?    7 Yes 3 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / hdhd

let the width of rectangle be x
so the length & breath is increased by 2x(draw on a paper
then only u'll understand)
so new total area along with walkway is (60+2x)*(20+2x)
so (60+2x)*(20+2x)-60*20=516
=>(60+2x)*(20+2x)=1716
=>(30+x)*(10+x)=429=33*13
=>x=3
which is da width of gateway

Is This Answer Correct ?    5 Yes 1 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / ravindra sharma

total area = 1200

area of walk way = 516 (given)
area of remaning part(R)(with out walkway path area)
=1200-516
=684
let,
length= l
width= b
area or R=>l*b =684
but,
l=60-2x (x is width of the walk way)
b=20-2x
so,
(60-2x)*(20-2x)=684
=> (x^2)-40x+129=0
=> x=36.46 (not possibal)
and
x=3.5379(so ans is 3.5)

Is This Answer Correct ?    13 Yes 12 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / prasad

formulae for area of path=
a=2w(l+b+2w)
where a is path area,
l=lenth
b=brieth
w =width
516=2w(60+20+2w)
finally we get 4w^2+160w-516=0
from options 3 is satisfied.

Is This Answer Correct ?    3 Yes 3 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / arunkumar

ground is rectangle shaped so if I consider the width the new length will be original length+2* width
therefore new L=60+2(3)==66
b=20+2(3)==26
(66*26)-(60*20)=516
condition satisfied ...Ans will be 3

Is This Answer Correct ?    0 Yes 0 No

.There is a rectangular Garden whose length and width are 60m X 20m.There is a walkway of uniform w..

Answer / shreyas

length : breadth is 6:2
6+2=8

512/8=64
64*6=384
64*2=132

384/60=6.5
132/20=6.5

The width of the pathways are 3.25

Is This Answer Correct ?    1 Yes 4 No

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