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Given:
11. public static void main(String[] args) {
12. Integer i = uew Integer(1) + new Integer(2);
13. switch(i) {
14. case 3: System.out.println(”three”); break;
15. default: System.out.println(”other”); break;
16. }
17. }
‘What is the result?
1 three
2 other
3 An exception is thrown at runtime.
4 Compilation fails because of an error on
line 12.
- 9 Answers
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Answer / venkata krishna
Hi,
Answer is 1 means three..
line 12 is executing sucuessfully ,after that i is 3 now
line 13 is switch also executed successfully and print the
three
| Is This Answer Correct ? | 8 Yes | 2 No |
In the line 12 .jus think new Integer(1) will result 1 and
new Integer(2) will result 2 so 1+2=3 which is stored in a i.
so the line 12 can b written as a Integer i=1+2;
the answer is 1) three
| Is This Answer Correct ? | 5 Yes | 1 No |
In the line 12 .jus think new Integer(1) will result 1 and
new Integer(2) will result 2 so 1+2=3 which is stored in a i.
so the line 12 can b written as a Integer i=1+3;
| Is This Answer Correct ? | 4 Yes | 1 No |
Answer / kumar
The above scenario using Wrapper class.The Wrapper class
allows arthmetic opertion(Boxing and unboxing the interget
numbers).So the result will be "three"
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / nirmal
Ans 4: Compilation fails because of an error on
line 12.
Reason: The operator + is undefined for the argument type
(s) java.lang.Integer, java.lang.Integer Cannot switch on a
value of type Integer. Only int values or enum constants
are permitted.
| Is This Answer Correct ? | 0 Yes | 4 No |
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