Compilation fails because of an error on

Given:
11. public static void main(String[] args) {
12. Integer i = uew Integer(1) + new Integer(2);
13. switch(i) {
14. case 3: System.out.println(”three”); break;
15. default: System.out.println(”other”); break;
16. }
17. }
‘What is the result?
1 three
2 other
3 An exception is thrown at runtime.
4 Compilation fails because of an error on
line 12.

Question Posted / harish

9 Answers
18206 Views
I also Faced
E-Mail Answers

Answer Posted / harish

Compilation fails because of an error on

Is This Answer Correct ?

5 Yes

12 No

Post New Answer View All Answers

Please Help Members By Posting Answers For Below Questions

Is an empty arraylist null?

1090

What is an escape character in java?

1036

Explain the pointers in Java?

1050

Explain runtime exceptions?

1175

Is it possible to specify multiple jndi names when deploying an ejb?

994

Why do we need autoboxing in java?

992

Can an interface extend another interface?

1053

What does main method?

977

What are the two ways of implementing multi-threading in java?

1503

How to convert string to char and vice versa?

1002

Difference between static synchronization vs. Instance synchronization?

1115

What is difference between core java and java ee?

895

Can you access the private method from outside the class?

965

What is the difference between call by reference and call by pointer?

957

What is the symbol for average?

1028