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How do you differentiate abstract class from interface?


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More Core Java Interview Questions

If I will write String s=new String("XYZ"); String s1=new String("XYZ"); if(s.equals(s1)){ sop("True"); } else{ sop("False"); } This program will give me "True". But When I am creating my own class suppose class Employee{ public Employee(String name); } Employee e= new Employee("XYZ"); Employee e1 = neew Employee("XYZ"); if(e.equals(e1)){ sop("True"); } else{ sop("False"); } Then it will give the output as "False". Can I know what is happening internally?

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