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What will be printed as the result of the operation below: #include<..> int x; int modifyvalue() { return(x+=10); } int changevalue(int x) { return(x+=1); } void main() { int x=10; x++; changevalue(x); x++; modifyvalue(); printf("First output:%d\n",x); x++; changevalue(x); printf("Second output:%d\n",x); modifyvalue(); printf("Third output:%d\n",x); }
2 111932)#include
6)swap(int x,y) { int temp; temp=x; x=y; y=temp; } main() { int x=2;y=3; swap(x,y); } after calling swap ,what are yhe values x&y?
3 2050118)struct base {int a,b; base(); int virtual function1(); } struct derv1:base{ int b,c,d; derv1() int virtual function1(); } struct derv2 : base {int a,e; } base::base() { a=2;b=3; } derv1::derv1(){ b=5; c=10;d=11;} base::function1() {return(100); } derv1::function1() { return(200); } main() base ba; derv1 d1,d2; printf("%d %d",d1.a,d1.b) o/p is a)a=2;b=3; b)a=3; b=2; c)a=5; b=10; d)none 19) for the above program answer the following q's main() base da; derv1 d1; derv2 d2; printf("%d %d %d",da.function1(),d1.function1(),d2.function1 ()); o/p is a)100,200,200; b)200,100,200; c)200,200,100; d)none 20)struct { int x; int y; }abc; you can not access x by the following 1)abc-->x; 2)abc[0]-->x; abc.x; (abc)-->x; a)1,2,3 b)2&3 c)1&2 d)1,3,4
1 10673write a program to swap bits in a character and return the value prototype of function char fun (char a, charb flag c) where fun returns a char, char a is a the value char b is the bit to be changed and flag c is the bit value for eg: x=fun(45,7,0) since 45 is 0010 0101 and ow x should contain the value 65 (0110 0101)
1 7413How to add two numbers without using arithmetic operators?
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18 44316Write a program to generate a pulse width frequency of your choise,which can be variable by using the digital port of your processor
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Hi how many types of software editions are there and their difference (like home editions, enterprise, standard etc) can u please help me
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