Why we use 250 ohm resister in series
hart communicator?
Answer Posted / carl_ellis
Answer #2 is not correct because the HART communicator is
not an analog input, it does not use a 1-5Vdc signal. A
HART communicator gets and display a transmitter's primary
variable (or other variables) as a digital value; NOT as an
analog value, not as a 1-5Vdc signal developed across an
analog input's resistor. I repeat, HART communications is
NOT analog in nature, it is digital.
The HART Foundation specifies a minimum resistance of 230
ohms, as described in answer #1, in order to develop the
1200 baud HART signal, that rides on top of the DC loop
current signal.
It's easy to prove that 250 ohms (for 1-5Vdc) is not a
requirement for HART communications as a bench test.
Take a 2 wire loop powered HART transmitter, connect a DC
power supply and use a 330 ohm resistor in series in the
loop. The communicator will work and the primary process
variable will be correct. Then try a 470 ohm resistor.
The 470 ohm resistor will work, as well, and the primary
variable will be correct.
Is This Answer Correct ? | 7 Yes | 1 No |
Post New Answer View All Answers
what is the advantage of submersible level transmitter compare to ultrasonic level transmitter?
use of split range ? where it is used ? in which control loop it is used ?
In Safe Guarding test what means by "Failed to Danger" ?
i am having information technology branh ....... can i prepare for psu exam
What is the formula of vabration sesore. i mean how to covert mils to volt plz share if any body knows very argent : my mai is merajalam143545@yahoo.com
which type of zones used for boiler? & why ?
How to fix back the valve actuator stem
3. Differentiate between ultrasonic flowmeter and radar type flow meter.
Conversions
How r the calculation of process line mpm.
How servomotor controls throttle valve of TURBINE?
why Fahrenheit unit of moistur analyzer transmitter
I installed the smartplant instrument v8, but can not be opened, that always said: "INTools 2007 hardlock no found". So Could you help me how to do for that?
May I have a brief note above the voltage barriers? Whats is the purpose? Please mail me if you've operational details, mail id: rajkumar.diice@gmail.com
Calculate the maximum pressure drop that can be allowed to occur across a control valve, so that we can prevent cavitation / flashing from occurring. Use the following formula: Δ P allow = Km (P1 – PvapourA) where, Δ P allow - the maximum allowable differential pressure for sizing purposes, or terminal pressure drop; Km- the valve recovery coefficient from the manufacturer’s catalogue; P1 - absolute inlet fluid pressure; PvapourA - absolute fluid vapour pressure at the inlet temperature; Use Atmospheric pressure = 101.3 kPa, P1 = 1200 kPa(g), PvapourA = 4 kPa, KM = 0.72