Answer Posted / kavinder

For M30 nominal mix, considering the ratio (1:1:2),

Cement = 1
Fine Agg = 1
Coarse Agg = 2

Total = 1+1+2=4

Considering the above ratio in grams i.e, (cement = 1 gm, Fine agg = 1 gm, Coarse agg = 2 gm) then

For 1 cum, 1/4 = 0.25 % will be filled.

Now, Volume of 1 bag of cement is 35 litres or 0.035 mL

Since, to maintain W/C ratio, the amount of cement & water should be equal.

Therefore, 1 gm of cement will require 0.035 mL of water.

0.25/0.035 = 7.15 approx. Bags or 357.5 kg of Cement.

or consider like this

1/((1+1+2)*0.035) = 7.15 approx. Bags or 357.5 kg of Cement (7.15 * 50 = 357.5), here ratio is 1 therefore 1*50=50

Fine Agg = 357.5 kg (7.15 * 50 = 357.5), here ratio is also 1 therefore 1*50=50

Coarse Agg = 715 kg (7.15 * 100 = 715), here ratio is 2 therefore 2*50=100

Adding all, 357.5+357.5+715 = 1430 kg

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