Answer Posted / randeepchaudhary

if we consider concrete grade M20(1:2:3)
1+2+3=6
wet volume 1.58cum
cement = 1/6x1.58=0.26cum
volume of one bag of cement = 0.033cum
total quantity of cement bag one CUM concrete =0.26/.033=7.87bags
7.87x50 kg=393kg

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