main() { int a = 65; printf(“%d %o %x”,a,a,a); } Output 65 101

main()
{
int a = 65;
printf(“%d %o %x”,a,a,a);
}

Output
65 101 41

Please explain me.How it is coming like that?

Question Posted / manojkumar

3 Answers
6009 Views
Excel, I also Faced
E-Mail Answers

Answers were Sorted based on User's Feedback

main() { int a = 65; printf(“%d %o %x”,a,a,a); } Output 65 101 41 Please expla..

Answer / neha

It prints the value of in decimal, octal, hexadecimal
format respectively.

Is This Answer Correct ?

6 Yes

0 No

main() { int a = 65; printf(“%d %o %x”,a,a,a); } Output 65 101 41 Please expla..

Answer / ruchika thakur

in octal,divide 65 by 8 and collect the remainder.it will
return 101....and in hexadecimal,divide 65 by 16 and again
collect the remainder...you will get 41......

THANKS

Is This Answer Correct ?

5 Yes

2 No

main() { int a = 65; printf(“%d %o %x”,a,a,a); } Output 65 101 41 Please expla..

Answer / chandan

printf(�%d %o %x�,a,a,a);
1) We can use ? sign instead of " sing in pintf statement .
2)First o/p value 65 ,is the decimal value of int a.
3)2nd o/p value 101 , is the octal value of int a.
i.e base is 8.
8^2 8^1 8^0
1 0 1
it Works 8^2 *1 + 8^1 *0 + 8^0*1 = 64*1 + 8*0 + 1*1=64+0+1=65
it is actual input decimal value.
Similarly,
4)3rd o/p value 41 , is the Hexadecimal value of int a.
i.e base is 16.
16^1 16^0
4 1
it Works 16^1 *4 + 16^0*1 = 16*4 + 1*1=64+1=65
it is actual input decimal value.

Is This Answer Correct ?

2 Yes

0 No

Post New Answer