Answer / vadivel t

Simple definitions:

Lvalue - is value which can be modified(it cannot be a
constant). And it can act as Rvalue too.

Rvalue - is value which can be able to fetch from the
memory, propably a constant. It can also act as Lvalue(if
it is not a constant).

Dont be confused... Lets hav example.

Example:
int a = 0, b = 10;

1.Rvalue
if(a)
{
...
...
...
}

here a is RValue(cos, as per definition, the value is able
to fetch from the memory)

2.One variable acting as L and R value
a = a + b;

here a + b; evaluated fist.. lets analise...
First a and b has to be fetched from the memory, by this
time, both will act as a Rvalue(as per definition)....
then a + b result shall be assigned to 'a'. Now 'a' will be
acting as a Lvalue. Cos u able to modify it...

So here 'a' can act as L as well as R value depends on the
situation.

3.a = 10;

Here 10 is Rvalue and 'a' ll act as Lvalue.
Hope u understand clearly.

Answer / ashish

An object is a contiguous region of memory storage. An
lvalue (pronounced: L value) is an expression that refers to
such an object. The original definition of lvalue referred
to "an object that can appear on the left-hand side of an
assignment." However, const objects are lvalues, and yet
they cannot appear on the left-hand side of an assignment.
An expression that can appear in the right-hand side of an
expression (but not in the left-hand side of an expression)
is an rvalue. For example:


#include <string>
using namespace std;
int& f();

void func()
{
int n;
char buf[3];
n = 5; // n is an lvalue; 5 is an rvalue
buf[0] = 'a'; //buf[0] is an lvalue, 'a' is an rvalue
string s1 = "a", s2 = "b", s3 = "c"; // "a", "b", "c" are
rvalues
s1 = // lvalue
s2 +s3; //s2 and s3 are lvalues that are implicitly
converted to rvalues
s1 =
string("z"); // temporaries are rvalues
int * p = new int; // p is an lvalue; 'new int' is an
rvalue
f() = 0; // a function call that returns a reference is
an lvalue
s1.size(); // otherwise, a function call is an rvalue
expression
}


An lvalue can appear in a context that requires an rvalue;
in this case, the lvalue is implicitly converted to an
rvalue. An rvalue cannot be converted to an lvalue.
Therefore, it is possible to use every lvalue expression in
the example as an rvalue, but not vice versa.

I need testPalindrome and removeSpace #include <stdio.h> #define SIZE 256 /* function prototype */ /* test if the chars in the range of [left, right] of array is a palindrome */ int testPalindrome( char array[], int left, int right ); /* remove the space in the src array and copy it over to the "copy" array */ /* set the number of chars in the "copy" array to the location that cnt points t */ void removeSpace(char src[], char copy[], int *cnt); int main( void ) { char c; /* temporarily holds keyboard input */ char string[ SIZE ]; /* original string */ char copy[ SIZE ]; /* copy of string without spaces */ int count = 0; /* length of string */ int copyCount; /* length of copy */ printf( "Enter a sentence:\n" ); /* get sentence to test from user */ while ( ( c = getchar() ) != '\n' && count < SIZE ) { string[ count++ ] = c; } /* end while */ string[ count ] = '\0'; /* terminate string */ /* make a copy of string without spaces */ removeSpace(string, copy, &copyCount); /* print whether or not the sentence is a palindrome */ if ( testPalindrome( copy, 0, copyCount - 1 ) ) { printf( "\"%s\" is a palindrome\n", string ); } /* end if */ else { printf( "\"%s\" is not a palindrome\n", string ); } /* end else */ return 0; /* indicate successful termination */ } /* end main */ void removeSpace(char src[], char copy[], int *cnt) { } int testPalindrome( char array[], int left, int right ) { }

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