what happen when unit step signal is applied to a
integrater circuit.explain with graph
Answers were Sorted based on User's Feedback
Answer / srinivas
integrator accumulates the value
therefore the o/p will be a linear line of the form y=mx+c
where c=initial vtg on integrator
| Is This Answer Correct ? | 55 Yes | 6 No |
Answer / jitendra agrawal
the transfer function of integrator is (1/s) if u integrate
this over a time period of infinity then we will get a ramp
wave whose transfer function is (1/s^2)
| Is This Answer Correct ? | 32 Yes | 0 No |
Answer / sattar
the output of the integrator will be a ramp signal with
slope (-)/(+) 1/Rc ,where Rc is the time constant of the
integrator.It will continue to be in ramp nature,until it
goes to saturation stage.
| |
| | ooooooooooooooo
| (STEP I/P SIGNAL) | o
.................... | o
| | o (ramp with slope 1/rc)
| | o
|___________________ |o_______________________
| Is This Answer Correct ? | 22 Yes | 3 No |
Answer / raj chakraborty
ans: ramp signal.
unit step signal is given as,
u(t)=1,for t>=0.
now integrate this function_____over 0 to t;
this will give you,
t-------as integrated value(which is ramp signal)
I think this site do not support to drew graphs
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / raj chakraborty
ans: ramp signal.
unit step signal is given as,
u(t)=1,for t>=0.
now integrate this function_____over 0 to t;
this will give you,
t-------as integrated value(which is ramp signal)
I think this site do not support to drew graphs
| Is This Answer Correct ? | 4 Yes | 0 No |
Answer / krishna
by considering time constant equal to 1,then apply input as
unit step signal as input.here integration of unit signal is
ramp signal.so we get output as ramp signal
| Is This Answer Correct ? | 3 Yes | 0 No |
Answer / jitendra kandpal
ans is ramp fn with constant slope
integration of u(t)= 1/s*(laplace transform of u(t))
= 1/s*1/s=1/s^2
by taking inverse laplace transform i.e= r(t) (ramp function)
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / saidesh kumar
when we integrate a constant w.r.t a variable we get the
same variable as output. so unit step integration gives ramp
as the output.Integrator is simply a low pass filter.
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / greeshmaja
exponential settling to the value 1...this is the voltage
rise across the capacitor as it charges
| Is This Answer Correct ? | 6 Yes | 17 No |
Answer / vivek
when unit step signal is applied to a
integrater circuit,we will gaet a triangular wave.since we
know,integration of constant becomes one degree equation.
| Is This Answer Correct ? | 12 Yes | 32 No |
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