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Imagine a triangle of coins on a table so that the first row
has one coin in it and the second row
has two coins in it and so on. If you can only move one coin
at a time, how many moves does it take
to make the triangle point the other way?
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Answer / sriram
HINT:-> first row in the triangle has one coin
o
HINT2:->second row has twpo coins.
o
o o
solution:
drop(move ) the coin horizontally below the second row
coins ,and the triangle becomes upside down!
o o
o
| Is This Answer Correct ? | 1 Yes | 0 No |
Answer / gandhi kumar
just three moves u see its sort of simple o o o o
o o o
0 0
0
is to be achieved
so 0
0 0
0 0 0
0 0 0 0
x1
here2 0 0 here3
0 0 0
x2 0 0 x3
here1
| Is This Answer Correct ? | 2 Yes | 2 No |
Answer / guest
For a triangle with two row it is one, for a triangle with
three rows it is two, for a triangle
with four rows it is three.
For a traingle with five rows is it four?
It takes 5 moves to make the triangle with 5 rows point the
other way.
0 = a coin that has not been moved.
X = the old position of the moved coin
8 = the new position of the moved coin.
________X
_______X X
____8 0 0 0 8
_____0 0 0 0
____X 0 0 0 X
_______8 8
________8
For traingle of any number of rows, the optimal number of
moves can be achieved by moving the
vertically symmetrical coins i.e. by moving same number of
coins from bottom left and right, and
remaining coins from the top.
For a triangle with an odd number of rows, the total moves
require are :
(N2/4) - (N-4) Where N = 4, 6, 8, 10, ...
For a triangle with even number of rows, the total moves
require are :
((N2-1)/4) - (N-4) Where N = 5, 7, 9, 11, ...
| Is This Answer Correct ? | 2 Yes | 4 No |
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