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A circular road runs round a circular ground. If the
difference between the circumference of the outer circle
and inner circle is 44 meters, find the width of the road?
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Answer / suman
(2*PI*R)-(2*PI*r)=44
2*(22/7)(R-r)=44
R-r=(44*7)/44
Road width=(R-r)=7 meters
| Is This Answer Correct ? | 13 Yes | 3 No |
Answer / santanu chakraborty
2#(r1-r2)=44
or, r1-r2=7
so the width is 7m
| Is This Answer Correct ? | 9 Yes | 0 No |
Answer / priyanka thakare
2#r1-2#r2=44
2#(r1-r2)=44
r1-r2=44/2#
//here #=3.14//
r1-r2=7m
| Is This Answer Correct ? | 4 Yes | 2 No |
Answer / srinivas panguluri
circumference of a circle = 2#r or #d
2#(r2-r1) = 44
r2-r1 = 44/2#
=14
| Is This Answer Correct ? | 14 Yes | 18 No |
Answer / vignesh1988i
THE WIDTH OF THE ROAD IS 7.6meters.......
given that (2*3.14*r1)-(2*3.14*r)=44
2*3.14(r1-r)=44
r1-r=22/3.14
r1-r= 7.6m
thank u
| Is This Answer Correct ? | 3 Yes | 13 No |
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