Answer / priya

select coloumn_name ,count(*) from table_name
group by coloumn_name
having count(*) > 1;

Answer / babu

Try this,
select col1,count(col1) from tab1
group by col1 having count(col1)>1;

If you want to delete these duplicate entries, use:
delete from tab1 where col1 in (select a.col1 from
(select col1,count(col1) from tab1
group by col1 having count(col1)>1) a);

Answer / purushotham

select column,count(1) from a
group by column
having count(1)>1;

Answer / dev

Hi,
There are many ways to do it.

One of that is ,

select count(0) from tab1 a
where a.rowid > any (select b.rowid from tab1 b where
a.col1 =b.col1);

Answer / akki julak

select count(empno)-count(distinct(empno)) from emp;

Answer / ajmal khan

There are many way to count the duplicate row in a table
select count(column_name)-count(distinct(column_name)) from
table_name;

Answer / suresh a

select sum(count(col1) -1) from emp
group by col1 having count(col1) > 1

Answer / shalu

select count(*) from table_name group by column1,column2...
having count(*) > 1

Answer / sravan

Hi here is another way to solve this

SELECT NAME, COUNT(NAME) FROM TABLE_NAME
WHERE NAME IN (SELECT NAME FROM TABLE_NAME
GROUP BY NAME
HAVING COUNT(NAME)>1)
GROUP BY NAME;

thanks

Answer / satheesh

SELECT COUNT(*)
FROM TABLE A
WHERE ROWID NOT IN (SELECT MAX(ROWID)
FROM TABLE B
WHERE A.COL1 = B.COL1);--UNIQUE COLUMN

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