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A train travels a certain distance taking 7 hrs in forward
journey, during the return journey increased speed 12km/hr
takes the times 5 hrs.What is the distance traveled
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Answer / sanjay
In this case the distance is the CONSTANT.
Distance = time *Velocity = K
Consider the velocity in the first case as x
then x*7 = (x+12)*5
x=30.
the distance is 7x = 210 kms.
| Is This Answer Correct ? | 32 Yes | 6 No |
Answer / anuj pandey
s=d/t
s=x/7 where x is the distance traveled.
s+12=x/5
s=x-60/5
x-60/5=x/7 taking the value of s .
7x-420=5x
2x=420
x=210
kms is the answer
| Is This Answer Correct ? | 13 Yes | 11 No |
Answer / manopriya
Distance= Speed*Time
Let Distance be x
Let Train Travels a certain distance taking 7hrs in forward
journey be A*7
Let Return journey increased speed and train travels in
same distance be (A+12)*5
X= A*7= (A+12)*5
X=7A=5A+60
X=2A=60
X=A=30
X=30
Distance is 30kms
| Is This Answer Correct ? | 14 Yes | 15 No |
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