Can any body tell me the procegure about how to use Super
Position Theorem to solve any electronics circuit.Please
tell me all the steps which used in Super Position
Theorem.Thanks
Answers were Sorted based on User's Feedback
Answer / walter
Superposition just means that you evaluate each individual
source's influence on the circuit one at a time, and then
just add it all up to get the total result.
To start, short all voltage sources but one (in the
schematic, not in real life!!!) and calculate all values
and polarities. Then you short that one and unshort one of
the originally shorted ones, and recalculate all the values
again, taking note of polarities again. Repeat this
procedure until all voltage sources have been the one that
was not shorted. Then you simply add up all the results,
taking the polarities into consideration of course. This
works for loops, double loops, triple, and by using your
results over and over, you can reduce the circuit until all
of it is done. It is tedius but works.
If you have current sources, you do not short them (that
all but one at a time business above) but open them all but
one at each time. Then you just do the same thing as above,
using currents as your knowns, that is if they are which
part is known. Could be that is not the case, maybe they
give you current and resistance and want the voltage, who
knows?
If you have both current and V sources, do the same thing,
just use one at a time, and calculate whichever you can,
voltage everywhere or current everywhere, and add that all
up in the end. Some may be more complicated than others.
Currents can't flow through an open, voltages can't produce
potential with a short. That is how each influence is
isolated. There is nothing wrong in the first answer
really, because voltages across resistors are not typically
needed to be assigned a polarity unless it is in two or
more loops. The second answer seems to think the top rail
should be the + which is traditional and such but the first
answer defined it differently which is fine. But . . . It
does not address superposition really. Hope that all helps.
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Answer / nagasrinu
the signs provided by u for voltages are wrong i think
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / venson eyang
Hi, this example might help...
Series Opposing
-voltage sources will subtract
(higher voltage minus lower voltage)
-same polarity connection
ex. draw a series circuit ---------->
(source1) V1=10v (-)(upper)(+)(lower), R1= 100, R2 = 75,
(source2) V2=35v (-)(upper)(+)(lower)
------R1-----------R2---------
| |
| |
V1 V2
| |
| |
------------------------------
VT (Voltage Total) = (V2)35v - (V1)10v
= 25v
VR1 = R1/RTxVT = 100/175x25 = 14.285v
VR2 = R2/RTxVT = 75/175x25 = 10.7142v
check = VR1+VR2 = 24.9992v or 25v (VT)
sorry for the drawing :). dunno yet how to solve parallel
or series parallel, if there is.. (0,,0).
| Is This Answer Correct ? | 0 Yes | 4 No |
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