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In the General meeting of "Friends Club", Sameer said, "The
repairs to the Club will come to a total of Rs 3120 and I
propose that this amount should be met by the members, each
paying an equal amount."
The proposal was immediately agreed. However, four members
of the Club chose to resign, leaving the remaining members
to pay an extra Rs 26 each.
How many members did the Club originally have?
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Answer / guest
The Club originally had 24 members.
Assume that there were initially N members.
As 4 members resigned and remaining members paid Rs 26 each,
it means that total amount of 4 members is equal to Rs 26
each from remaining (N-4) members. Thus,
4 * (3120 / N) = 26 * (N - 4)
12480 = 26N2 - 104N
26N2 - 104N - 12480 = 0
Solving the quadratic equation we get N=24.
Hence, the Club originally had 24 members.
| Is This Answer Correct ? | 24 Yes | 1 No |
Answer / windflower
let the number of club members be N
Then each member will have to pay 3120/N
4 members resigned and therefore each member should pay an extra of rs.26
thus (3120/N +26)(N-4)=3120
if you simplify further, you will get N=24
| Is This Answer Correct ? | 6 Yes | 1 No |
Answer / vignesh
IN each of the (N-4) pays rs 26,
thn,, 26*(N-4)=3120
N=124..(total members)..
the above solutions does not give
3120/20 is not equal to 26
bt....3120/20 gives 26..
| Is This Answer Correct ? | 0 Yes | 6 No |
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