find a number whether it is even or odd without using any
control structures and relational operators?
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Answer / ramya
A number anded with the lower number that is n & (n - 1) =
0 then it is even if it is anything else it is odd
odd_even (int n)
{
if (!(n & (n -1))
number is odd
else
number is even
}
| Is This Answer Correct ? | 9 Yes | 29 No |
Answer / guest
#include<stdio.h>
#include<conio.h>
void main()
{
int x;
if(x%2==0)
printf("even");
else
printf("odd");
getch();
}
| Is This Answer Correct ? | 4 Yes | 25 No |
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