When an inductor tunes at 200 KHz with 624 pF capacitor and
at 600 KHz with 60.4 pF capacitor then the self capacitance
of the inductor would be
a) 8.05 pF b) 10.05pF c.) 16.01pF d.) 20.01pF
Answers were Sorted based on User's Feedback
Answer / rs90
the inherent self-capacitance of the inductor coil will be
in parallel with its inductance..so in a tuned circuit this
capacitance will be in parallel with the given external
capacitor..so the resultant capacitance is the sum of these two.
Let the resultant capacitance in the first and 2nd case be
C1 and C2 resp.Since the resonant frequency is inversely
proportional to sqrt(LC) and L being same in both cases..we
can write
C1/C2 = (f2)² /(f1)²
where C1=624 pF C2=60.4 pF f1=200 KHz f2=600 KHz
Solving we get C1/C2=9
now C1=624 + x
C2=60.4 + x
x=self capacitance
put these in above eqn to get x= 10.05
Is This Answer Correct ? | 10 Yes | 1 No |
Answer / niloy datta
sir, dont just give us the answer, tell us how..
Is This Answer Correct ? | 3 Yes | 0 No |
What are power diodes?
i cleared the written xam. for the post of atc now what i am going to prepare for the interview plz.guide me i dnt wanna loose this organisation bcoz its my dream company
0 Answers AAI Airports Authority Of India,
What is the formula for non inverting amplifier?
what's the cut in voltage for a led?
what is an excitation table?
how much salary r u expecting?
Define the limitations in the operation conditions of a p-n junction.
What is commutation angle or overlap angle?
Explain the working of voltage commutated chopper with aid of circuit diagram and necessary waveforms. Derive an expression for its output voltage?
What is an excess-3 code?
What kind of modulation is used for land phone communication systems?
What is the output of the lexical analyser?