wap to print "hello world" without using the main function.
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Answer / sivasankar
#include<stdio.h>
#include<conio.h>
#define ksrct main()
ksrct
{
clrscr();
printf("hello world");
getch();
}
| Is This Answer Correct ? | 1 Yes | 1 No |
Answer / vaibhav
@Deepika some correction:
#include<stdio.h>
#define decode(s,t,u,m,p,e,d) m##s##u##t
#define begin decode(a,n,i,m,a,t,e)
int begin()
{
printf("Hello World");
}
| Is This Answer Correct ? | 0 Yes | 1 No |
Answer / ranjan
#include<stdio.h>
#include<iostream.h>
class World
{
public:
World()
{
printf("Hello world");
}
}
world w1;
Here the object is declared globaly.so when the object is
defined it will call the constructor of that & that will
display the "hello world". no need to write main. as it is
global.
| Is This Answer Correct ? | 2 Yes | 4 No |
Answer / siva
#include<stdio.h>
#include<conio.h>
#define siva main
siva()
{
clrscr();
printf("hello world");
getch();
return 0;
}
| Is This Answer Correct ? | 3 Yes | 5 No |
Answer / vignesh1988i
the basic format or the first executable code line is the
main function in C.... so if we try to print the anything
without main we are trying to modify the basic concepts of C
and this will not look nice....
thank u
| Is This Answer Correct ? | 20 Yes | 24 No |
Answer / kk
And some deserts for Mr. Vignesh1988i ..
For your kind attention sir.. Method main() is not the first
line in any executable... Have you ever heard of
initialization??
Yes you can say what ever the developer writes in any
program starts in main()..
| Is This Answer Correct ? | 3 Yes | 11 No |
Answer / kk
main() method is the entry point for any c/c++ program which
is compiled/linked as executable. C/C++ does not force
anyone to use only main() method as the entry point. This is
only the default behavior and can be changed. This is
generally slightly different for different compiler. But you
can do this.. Simply define any other method say noMe() to
be the entry point for the executable.
Who the hell uses main()to do main stuffs in any
executable.. It should have been called something like
start() ot begin().. :)
Well this is not the answer.. Just little guidance..
| Is This Answer Correct ? | 3 Yes | 16 No |
Answer / thirupathi reddy
by using the comment lines we can get the output
| Is This Answer Correct ? | 7 Yes | 35 No |
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I need help with the following lab. Can anyone explain it to me on how to approach this problem. Coding would be great too !!! No busy waiting allowed. Remember that Java monitors are 'signal and continue'. The input data is called the database (DB). In this problem, it consists of a single variable initialized in the main thread, to contain the current time of day in HH:MM:SS:mmm format (mmm is milliseconds) truncated to 3 digits. Threads follow these rules: 1. Readers may all attempt to read at the same time, but NOT if a writer is writing (i.e.; the writer is in the monitor. 2. Writing is exclusive (only 1 writer at a time, no readers while writing). 3. Options: (to be specified by instructor) a. Readers have absolute priority over writers. b. Writers have absolute priority over readers c. When a reader arrives and a writer is waiting, the reader is suspended behind the writer instead of being admitted immediately. Thus, a writer waits for readers that were running when it arrived, but does not to wait for new readers. You may program this in C++ or Java. There are 4 controlling input values: 1. r – number of readers 2. w – number of writers 3. R – delay for a reader to restart 4. W – delay for a writer to restart Create the following program consisting of 1 main process (your main program) with n threads: 1. The main thread: a. Creates the 'n' threads needed. Of these, r of them are readers and w of them are writers. Starts all readers and writers. b. Waits for all 'n' threads to complete. You may use any method to detect when they are all complete. c. Prints out the resulting outputs from the threads. 2. Threads: a. When a thread starts to run, it immediately tries to enter the monitor. b. A reader thread reads the DB, outputs the exact message below, then exits: >>> DB value read =: HH:MM:SS:mmm by reader number: rr where the underlined text is replaced with actual data. c. A writer thread updates the DB with a new value (from the system time), outputs the exact message below, then exits: *** DB value set to: HH:MM:SS:mmm by writer number: ww where the underlined text is replaced with actual data. d. Each thread accesses the data a total of 10 times, exiting, then re-entering the monitor after each access. Hints: 1. File access *might* not be thread-safe, so you should be prepared to handle this. Read the documentation for the language you are using. 2. Suggested values for delays are: a. If looping, R >=1,000,000 and W>=100,000 b. If using “sleep”, then R=100 ms, W=50 ms. Additional: • Thread output is to ONE file used by ALL threads (so you need to synchronize access to it). • Readers must provide sufficient delay that results are useful (delay by R before re-trying). R is another input value. • Writers must also delay. Delay by W, updating the DB each time. W is an input. • Test your program with AT LEAST TWO different sets of values for r and w (#s of readers and writers) plus this set: r = 4, w=2. Basic operation of a thread: attempt to enter the monitor. If unsuccessful, you get put on a queue. When you get in, read or write the data (depending on type of thread), exit the monitor, wait the required delay amount, then try again. Repeat 10 times.
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