Answer / guest

Divide 1000 building numbers into groups of 100 each as
follow:
(1..100), (101..200), (201..300), ....... (901..1000)

For the first group, sign-maker will need 11 zeroes.
For group numbers 2 to 9, he will require 20 zeroes each.
And for group number 10, he will require 21 zeroes.

The total numbers of zeroes required are
= 11 + 8*20 + 21
= 11 + 160 + 21
= 192

Answer / vijay kumar

192 Zeroes

Answer / madhukar

192

Answer / yogita jagtap

(1-100)=11 zeroes
(101-200)=20 zeros *8 groups
(901-1000)=21 zeroes
11 + 8*20 + 21
= 11 + 160 + 21 = 192

Answer / praveen

10 to 100--->11
////////
101 to 199:
101 tt 110-->10
111 to 200--->12
//////////////////
total 101 to 200--->22
201 to 300--->22
301 to 400--->22
//
900 to 1000-->23

so total no of zeros=11 + 8(22) + 23 =210

Answer / jaskaran

201

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