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A certain street has 1000 buildings. A sign-maker is
contracted to number the houses from 1 to 1000. How many
zeroes will he need?
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Answer / guest
Divide 1000 building numbers into groups of 100 each as
follow:
(1..100), (101..200), (201..300), ....... (901..1000)
For the first group, sign-maker will need 11 zeroes.
For group numbers 2 to 9, he will require 20 zeroes each.
And for group number 10, he will require 21 zeroes.
The total numbers of zeroes required are
= 11 + 8*20 + 21
= 11 + 160 + 21
= 192
| Is This Answer Correct ? | 132 Yes | 11 No |
Answer / yogita jagtap
(1-100)=11 zeroes
(101-200)=20 zeros *8 groups
(901-1000)=21 zeroes
11 + 8*20 + 21
= 11 + 160 + 21 = 192
| Is This Answer Correct ? | 9 Yes | 1 No |
Answer / praveen
10 to 100--->11
////////
101 to 199:
101 tt 110-->10
111 to 200--->12
//////////////////
total 101 to 200--->22
201 to 300--->22
301 to 400--->22
//
900 to 1000-->23
so total no of zeros=11 + 8(22) + 23 =210
| Is This Answer Correct ? | 2 Yes | 28 No |
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