There are 3 persons X, Y and Z. On some day, X lent
tractors to Y and Z as many as they had. After a month Y
gave as many tractors to X and Z as many as they have.
After a month Z did the same thing. At the end of this
transaction each one of them had 24.
Find the tractors each originally had?
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Answer / sweta
x had 39 tractors
y had 21 tractors
z had 12 tractors
| Is This Answer Correct ? | 49 Yes | 3 No |
Answer / abdul hamid
before z lent x has 12 trac y has 12 z has 48
before y lent x has 6 trac z has 24 y has 42
before x lent x has 39
y has 21
z has 12
| Is This Answer Correct ? | 10 Yes | 1 No |
Answer / sambasivan
X - 39 Y 21 and Z 12 is correct. another answer which
says X -36 is not correct because after giving Y and Z he
will be left with zero.
| Is This Answer Correct ? | 5 Yes | 1 No |
Answer / jack
In the question it didnt said that X want to lend his
tractors to Y and Z. Similarly to others.... Hence it is
not an compulsary that X should lend tractors from him to
others. Hence 6 is answer.
6 6 6
6 12 12
12 12 24
24 24 24
| Is This Answer Correct ? | 1 Yes | 5 No |
(7*7=49)(4*9=36)(3*6=18) (1*8=8)
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